Optimal. Leaf size=368 \[ \frac {\left (2 c^2-15 c d+76 d^2\right ) \tan (e+f x)}{15 f (c-d)^3 \left (a^3 \sec (e+f x)+a^3\right ) (c+d \sec (e+f x))^2}-\frac {d^3 \left (20 c^2+30 c d+13 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {c-d} \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c+d}}\right )}{a^3 f (c-d)^{11/2} (c+d)^{5/2}}+\frac {d \left (4 c^3-30 c^2 d+146 c d^2+195 d^3\right ) \tan (e+f x)}{30 a^3 f (c-d)^4 (c+d) (c+d \sec (e+f x))^2}+\frac {d \left (4 c^4-30 c^3 d+142 c^2 d^2+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 a^3 f (c-d)^5 (c+d)^2 (c+d \sec (e+f x))}+\frac {(2 c-11 d) \tan (e+f x)}{15 a f (c-d)^2 (a \sec (e+f x)+a)^2 (c+d \sec (e+f x))^2}+\frac {\tan (e+f x)}{5 f (c-d) (a \sec (e+f x)+a)^3 (c+d \sec (e+f x))^2} \]
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Rubi [A] time = 0.71, antiderivative size = 414, normalized size of antiderivative = 1.12, number of steps used = 9, number of rules used = 7, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {3987, 103, 151, 152, 12, 93, 205} \[ \frac {d^3 \left (20 c^2+30 c d+13 d^2\right ) \tan (e+f x) \tan ^{-1}\left (\frac {\sqrt {c+d} \sqrt {a \sec (e+f x)+a}}{\sqrt {c-d} \sqrt {a-a \sec (e+f x)}}\right )}{a^2 f (c-d)^{11/2} (c+d)^{5/2} \sqrt {a-a \sec (e+f x)} \sqrt {a \sec (e+f x)+a}}+\frac {\left (142 c^2 d^2-30 c^3 d+4 c^4+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 f (c-d)^5 (c+d)^2 \left (a^3 \sec (e+f x)+a^3\right )}-\frac {3 d (2 c+d) \tan (e+f x)}{2 f \left (c^2-d^2\right )^2 (a \sec (e+f x)+a)^3 (c+d \sec (e+f x))}-\frac {d \tan (e+f x)}{2 f \left (c^2-d^2\right ) (a \sec (e+f x)+a)^3 (c+d \sec (e+f x))^2}+\frac {\left (-26 c^2 d+4 c^3-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a f (c-d)^4 (c+d)^2 (a \sec (e+f x)+a)^2}+\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 f (c-d)^3 (c+d)^2 (a \sec (e+f x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 12
Rule 93
Rule 103
Rule 151
Rule 152
Rule 205
Rule 3987
Rubi steps
\begin {align*} \int \frac {\sec (e+f x)}{(a+a \sec (e+f x))^3 (c+d \sec (e+f x))^3} \, dx &=-\frac {\left (a^2 \tan (e+f x)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a-a x} (a+a x)^{7/2} (c+d x)^3} \, dx,x,\sec (e+f x)\right )}{f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {\tan (e+f x) \operatorname {Subst}\left (\int \frac {a^2 (2 c+3 d)-4 a^2 d x}{\sqrt {a-a x} (a+a x)^{7/2} (c+d x)^2} \, dx,x,\sec (e+f x)\right )}{2 \left (c^2-d^2\right ) f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}-\frac {\tan (e+f x) \operatorname {Subst}\left (\int \frac {a^4 \left (2 c^2+21 c d+13 d^2\right )-9 a^4 d (2 c+d) x}{\sqrt {a-a x} (a+a x)^{7/2} (c+d x)} \, dx,x,\sec (e+f x)\right )}{2 a^2 \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}+\frac {\tan (e+f x) \operatorname {Subst}\left (\int \frac {-a^6 \left (4 c^3-22 c^2 d-106 c d^2-65 d^3\right )-2 a^6 d \left (2 c^2+39 c d+22 d^2\right ) x}{\sqrt {a-a x} (a+a x)^{5/2} (c+d x)} \, dx,x,\sec (e+f x)\right )}{10 a^5 (c-d) \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}+\frac {\left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a (c-d)^4 (c+d)^2 f (a+a \sec (e+f x))^2}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}-\frac {\tan (e+f x) \operatorname {Subst}\left (\int \frac {a^8 (c+d) \left (4 c^3-30 c^2 d+146 c d^2+195 d^3\right )+a^8 d \left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) x}{\sqrt {a-a x} (a+a x)^{3/2} (c+d x)} \, dx,x,\sec (e+f x)\right )}{30 a^8 (c-d)^2 \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}+\frac {\left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a (c-d)^4 (c+d)^2 f (a+a \sec (e+f x))^2}+\frac {\left (4 c^4-30 c^3 d+142 c^2 d^2+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 (c-d)^5 (c+d)^2 f \left (a^3+a^3 \sec (e+f x)\right )}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}+\frac {\tan (e+f x) \operatorname {Subst}\left (\int \frac {15 a^{10} d^3 \left (20 c^2+30 c d+13 d^2\right )}{\sqrt {a-a x} \sqrt {a+a x} (c+d x)} \, dx,x,\sec (e+f x)\right )}{30 a^{11} (c-d)^3 \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}+\frac {\left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a (c-d)^4 (c+d)^2 f (a+a \sec (e+f x))^2}+\frac {\left (4 c^4-30 c^3 d+142 c^2 d^2+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 (c-d)^5 (c+d)^2 f \left (a^3+a^3 \sec (e+f x)\right )}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}+\frac {\left (d^3 \left (20 c^2+30 c d+13 d^2\right ) \tan (e+f x)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a-a x} \sqrt {a+a x} (c+d x)} \, dx,x,\sec (e+f x)\right )}{2 a (c-d)^3 \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}+\frac {\left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a (c-d)^4 (c+d)^2 f (a+a \sec (e+f x))^2}+\frac {\left (4 c^4-30 c^3 d+142 c^2 d^2+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 (c-d)^5 (c+d)^2 f \left (a^3+a^3 \sec (e+f x)\right )}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}+\frac {\left (d^3 \left (20 c^2+30 c d+13 d^2\right ) \tan (e+f x)\right ) \operatorname {Subst}\left (\int \frac {1}{a c-a d-(-a c-a d) x^2} \, dx,x,\frac {\sqrt {a+a \sec (e+f x)}}{\sqrt {a-a \sec (e+f x)}}\right )}{a (c-d)^3 \left (c^2-d^2\right )^2 f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}\\ &=\frac {\left (2 c^2+39 c d+22 d^2\right ) \tan (e+f x)}{10 (c-d)^3 (c+d)^2 f (a+a \sec (e+f x))^3}+\frac {\left (4 c^3-26 c^2 d-184 c d^2-109 d^3\right ) \tan (e+f x)}{30 a (c-d)^4 (c+d)^2 f (a+a \sec (e+f x))^2}+\frac {d^3 \left (20 c^2+30 c d+13 d^2\right ) \tan ^{-1}\left (\frac {\sqrt {c+d} \sqrt {a+a \sec (e+f x)}}{\sqrt {c-d} \sqrt {a-a \sec (e+f x)}}\right ) \tan (e+f x)}{a^2 (c-d)^{11/2} (c+d)^{5/2} f \sqrt {a-a \sec (e+f x)} \sqrt {a+a \sec (e+f x)}}+\frac {\left (4 c^4-30 c^3 d+142 c^2 d^2+525 c d^3+304 d^4\right ) \tan (e+f x)}{30 (c-d)^5 (c+d)^2 f \left (a^3+a^3 \sec (e+f x)\right )}-\frac {d \tan (e+f x)}{2 \left (c^2-d^2\right ) f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))^2}-\frac {3 d (2 c+d) \tan (e+f x)}{2 \left (c^2-d^2\right )^2 f (a+a \sec (e+f x))^3 (c+d \sec (e+f x))}\\ \end {align*}
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Mathematica [C] time = 7.83, size = 1096, normalized size = 2.98 \[ \frac {4 \cos ^4\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \sec \left (\frac {e}{2}\right ) \left (23 d \sin \left (\frac {e}{2}\right )-8 c \sin \left (\frac {e}{2}\right )\right ) \sec ^6(e+f x)}{15 (d-c)^4 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}+\frac {\left (20 c^2+30 d c+13 d^2\right ) \cos ^6\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \left (-\frac {8 i \tan ^{-1}\left (\sec \left (\frac {f x}{2}\right ) \left (\frac {\cos (e)}{\sqrt {c^2-d^2} \sqrt {\cos (2 e)-i \sin (2 e)}}-\frac {i \sin (e)}{\sqrt {c^2-d^2} \sqrt {\cos (2 e)-i \sin (2 e)}}\right ) \left (i c \sin \left (e+\frac {f x}{2}\right )-i d \sin \left (\frac {f x}{2}\right )\right )\right ) \cos (e) d^3}{\sqrt {c^2-d^2} f \sqrt {\cos (2 e)-i \sin (2 e)}}-\frac {8 \tan ^{-1}\left (\sec \left (\frac {f x}{2}\right ) \left (\frac {\cos (e)}{\sqrt {c^2-d^2} \sqrt {\cos (2 e)-i \sin (2 e)}}-\frac {i \sin (e)}{\sqrt {c^2-d^2} \sqrt {\cos (2 e)-i \sin (2 e)}}\right ) \left (i c \sin \left (e+\frac {f x}{2}\right )-i d \sin \left (\frac {f x}{2}\right )\right )\right ) \sin (e) d^3}{\sqrt {c^2-d^2} f \sqrt {\cos (2 e)-i \sin (2 e)}}\right ) \sec ^6(e+f x)}{(d-c)^5 (c+d)^2 (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}-\frac {2 \cos \left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \sec \left (\frac {e}{2}\right ) \sin \left (\frac {f x}{2}\right ) \sec ^6(e+f x)}{5 (d-c)^3 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}+\frac {4 \cos ^3\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \sec \left (\frac {e}{2}\right ) \left (23 d \sin \left (\frac {f x}{2}\right )-8 c \sin \left (\frac {f x}{2}\right )\right ) \sec ^6(e+f x)}{15 (d-c)^4 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}-\frac {8 \cos ^5\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \sec \left (\frac {e}{2}\right ) \left (7 \sin \left (\frac {f x}{2}\right ) c^2-44 d \sin \left (\frac {f x}{2}\right ) c+127 d^2 \sin \left (\frac {f x}{2}\right )\right ) \sec ^6(e+f x)}{15 (d-c)^5 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}+\frac {4 \cos ^6\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x)) \sec (e) \left (d^6 \sin (e)-c d^5 \sin (f x)\right ) \sec ^6(e+f x)}{c^2 (d-c)^4 (c+d) f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}-\frac {4 \cos ^6\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^2 \sec (e) \left (2 \sin (e) d^7-6 c \sin (e) d^6-c \sin (f x) d^6-11 c^2 \sin (e) d^5+6 c^2 \sin (f x) d^5+10 c^3 \sin (f x) d^4\right ) \sec ^6(e+f x)}{c^2 (d-c)^5 (c+d)^2 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3}-\frac {2 \cos ^2\left (\frac {e}{2}+\frac {f x}{2}\right ) (d+c \cos (e+f x))^3 \tan \left (\frac {e}{2}\right ) \sec ^6(e+f x)}{5 (d-c)^3 f (\sec (e+f x) a+a)^3 (c+d \sec (e+f x))^3} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.62, size = 2677, normalized size = 7.27 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.62, size = 1419, normalized size = 3.86 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.97, size = 365, normalized size = 0.99 \[ \frac {\frac {\frac {\left (\tan ^{5}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) c^{2}}{5}-\frac {2 \left (\tan ^{5}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) c d}{5}+\frac {\left (\tan ^{5}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) d^{2}}{5}-\frac {2 \left (\tan ^{3}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) c^{2}}{3}+\frac {10 \left (\tan ^{3}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) c d}{3}-\frac {8 \left (\tan ^{3}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) d^{2}}{3}+\tan \left (\frac {e}{2}+\frac {f x}{2}\right ) c^{2}-8 c d \tan \left (\frac {e}{2}+\frac {f x}{2}\right )+31 \tan \left (\frac {e}{2}+\frac {f x}{2}\right ) d^{2}}{\left (c^{3}-3 c^{2} d +3 c \,d^{2}-d^{3}\right ) \left (c^{2}-2 c d +d^{2}\right )}+\frac {16 d^{3} \left (\frac {-\frac {d \left (10 c^{2}-3 c d -7 d^{2}\right ) \left (\tan ^{3}\left (\frac {e}{2}+\frac {f x}{2}\right )\right )}{4 \left (c^{2}+2 c d +d^{2}\right )}+\frac {5 d \left (2 c +d \right ) \tan \left (\frac {e}{2}+\frac {f x}{2}\right )}{4 \left (c +d \right )}}{\left (\left (\tan ^{2}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) c -\left (\tan ^{2}\left (\frac {e}{2}+\frac {f x}{2}\right )\right ) d -c -d \right )^{2}}-\frac {\left (20 c^{2}+30 c d +13 d^{2}\right ) \arctanh \left (\frac {\tan \left (\frac {e}{2}+\frac {f x}{2}\right ) \left (c -d \right )}{\sqrt {\left (c +d \right ) \left (c -d \right )}}\right )}{4 \left (c^{2}+2 c d +d^{2}\right ) \sqrt {\left (c +d \right ) \left (c -d \right )}}\right )}{\left (c -d \right )^{5}}}{4 f \,a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.36, size = 655, normalized size = 1.78 \[ \frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5}{20\,a^3\,f\,{\left (c-d\right )}^3}-\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (\frac {3\,{\left (c+d\right )}^2}{4\,a^3\,{\left (c-d\right )}^5}-\frac {5}{2\,a^3\,{\left (c-d\right )}^3}+\frac {3\,\left (c+d\right )\,\left (\frac {5}{4\,a^3\,{\left (c-d\right )}^3}-\frac {3\,\left (c+d\right )}{4\,a^3\,{\left (c-d\right )}^4}\right )}{c-d}\right )}{f}-\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (\frac {5}{12\,a^3\,{\left (c-d\right )}^3}-\frac {c+d}{4\,a^3\,{\left (c-d\right )}^4}\right )}{f}-\frac {\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (-10\,c^2\,d^4+3\,c\,d^5+7\,d^6\right )}{{\left (c+d\right )}^2}+\frac {5\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (d^5+2\,c\,d^4\right )}{c+d}}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (2\,a^3\,c^7-10\,a^3\,c^6\,d+18\,a^3\,c^5\,d^2-10\,a^3\,c^4\,d^3-10\,a^3\,c^3\,d^4+18\,a^3\,c^2\,d^5-10\,a^3\,c\,d^6+2\,a^3\,d^7\right )-{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (a^3\,c^7-7\,a^3\,c^6\,d+21\,a^3\,c^5\,d^2-35\,a^3\,c^4\,d^3+35\,a^3\,c^3\,d^4-21\,a^3\,c^2\,d^5+7\,a^3\,c\,d^6-a^3\,d^7\right )-a^3\,c^7+a^3\,d^7-3\,a^3\,c\,d^6+3\,a^3\,c^6\,d+a^3\,c^2\,d^5+5\,a^3\,c^3\,d^4-5\,a^3\,c^4\,d^3-a^3\,c^5\,d^2\right )}+\frac {d^3\,\mathrm {atan}\left (\frac {1{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c^6-6{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c^5\,d+15{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c^4\,d^2-20{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c^3\,d^3+15{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c^2\,d^4-6{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,c\,d^5+1{}\mathrm {i}\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,d^6}{\sqrt {c+d}\,{\left (c-d\right )}^{11/2}}\right )\,\left (20\,c^2+30\,c\,d+13\,d^2\right )\,1{}\mathrm {i}}{a^3\,f\,{\left (c+d\right )}^{5/2}\,{\left (c-d\right )}^{11/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {\sec {\left (e + f x \right )}}{c^{3} \sec ^{3}{\left (e + f x \right )} + 3 c^{3} \sec ^{2}{\left (e + f x \right )} + 3 c^{3} \sec {\left (e + f x \right )} + c^{3} + 3 c^{2} d \sec ^{4}{\left (e + f x \right )} + 9 c^{2} d \sec ^{3}{\left (e + f x \right )} + 9 c^{2} d \sec ^{2}{\left (e + f x \right )} + 3 c^{2} d \sec {\left (e + f x \right )} + 3 c d^{2} \sec ^{5}{\left (e + f x \right )} + 9 c d^{2} \sec ^{4}{\left (e + f x \right )} + 9 c d^{2} \sec ^{3}{\left (e + f x \right )} + 3 c d^{2} \sec ^{2}{\left (e + f x \right )} + d^{3} \sec ^{6}{\left (e + f x \right )} + 3 d^{3} \sec ^{5}{\left (e + f x \right )} + 3 d^{3} \sec ^{4}{\left (e + f x \right )} + d^{3} \sec ^{3}{\left (e + f x \right )}}\, dx}{a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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